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Question
Stomach acid, a dilute solution of HCl can be neutralized by reaction with aluminium hydroxide \[\ce{Al(OH)3 + 3HCl (aq) -> AlCl3 + 3H2O}\]
How many milliliters of 0.1 M Al(OH)3 solution is needed to neutralize 21 ml of 0.1 M HCl?
Options
14 mL
7 mL
21 mL
none of these
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Solution
7 mL
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