Advertisements
Advertisements
Question
Starting with sodium chloride how would you proceed to prepare sodium peroxide.
Advertisements
Solution
First, NaCl is electrolysed to result in the formation of Na metal (Downs process).
This sodium metal is then heated on aluminium trays in air (free of CO2) to form its peroxide.
\[\ce{2Na + O_{2(air)} -> Na_2O_2}\]
RELATED QUESTIONS
Explain why is sodium less reactive than potassium?
Compare the alkali metals and alkaline earth metals with respect to (i) ionization enthalpy (ii) basicity of oxides and (iii) solubility of hydroxides
Compare the solubility and thermal stability of the following compound of the alkali metals with those of the alkaline earth metals.
Nitrates
Compare the solubility and thermal stability of the following compounds of the alkali metals with those of the alkaline earth metals.
Carbonates
Compare the solubility and thermal stability of the following compounds of the alkali metals with those of the alkaline earth metals.
Sulphates
Starting with sodium chloride how would you proceed to prepare sodium carbonate?
The hydroxides and carbonates of sodium and potassium are easily soluble in water while the corresponding salts of magnesium and calcium are sparingly soluble in water. Explain.
State as to why alkali metals are prepared by electrolysis of their fused chlorides?
How would you explain the following observation?
BeO is almost insoluble but BeSO4 in soluble in water.
How would you explain the following observation?
BaO is soluble but BaSO4 is insoluble in water.
How would you explain the following observation?
LiI is more soluble than KI in ethanol.
The s-block elements are characterised by their larger atomic sizes, lower ionisation enthalpies, invariable +1 oxidation state and solubilities of their oxosalts. In the light of these features describe the nature of their oxides, halides and oxosalts.
Which of the alkali metals form only the normal oxide, M2O on heating in the air?
The ratio of number of water molecules in Mohr's salt and potash alum is ______ × 10-1.
