Question

Starting with same initial conditions an ideal gas expands from volume \[V_A\] to \[V_B\] in three different ways. The work done by the gas is '\[W_1\]' if the process is purely adiabatic, '\[W_2\]' if it is purely isobaric and '\[W_3\]' if it is purely isothermal. Then ______.

Options

• \[W_1>W_2>W_3\]

• \[W_1<W_2<W_3\]

• \[W_2>W_3>W_1\]

• \[W_2<W_3<W_1\]

Answer 1

Starting with same initial conditions an ideal gas expands from volume \[V_A\] to \[V_B\] in three different ways. The work done by the gas is '\[W_1\]' if the process is purely adiabatic, '\[W_2\]' if it is purely isobaric and '\[W_3\]' if it is purely isothermal. Then \[W_2>W_3>W_1\].

Explanation:

The work done is given by the area under the P-V curve. From figure, the work done for isobaric process is maximum while that for adiabatic is minimum.i.e., \[W_2>W_3>W_1\]