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Question
Split 207 into three parts such that these parts are in A.P. and the product of the two smaller parts in 4623.
Sum
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Solution
Let the three parts in A.P. be (a – d), a and (a + d)
Then, (a – d) + a + (a + d) = 207
`\implies` 3a = 207
`\implies` a = `207/3` = 69
It is given that
(a – d) × a = 4623
`\implies` (69 – d) × 69 = 4623
`\implies` 69 – d = `4623/69` = 67
`\implies` d = 69 – 67 = 2
`\implies` a = 69 and d = 2
Thus, we have
a – d = 69 – 2 = 67
a = 69
a + d = 69 + 2 = 71
Thus, the three parts in A.P. are 67, 69 and 71.
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