Question

Specific conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm⁻¹. Calculate its molar conductivity.

Answer 1

Given:

Specific conductivity (κ) = 0.025 S cm⁻¹

Concentration (C) = 0.20 mol L⁻¹

To find:

Molar conductivity = ?

Calculations:

`Lambda_m = (kappa xx 1000)/C`

= `(0.025 xx 1000)/0.20`

= 125 S cm² mol⁻¹

∴ The molar conductivity of the given solution is 125 S cm² mol⁻¹.