Advertisements
Advertisements
Question
Some students planned a picnic. The total budget for food was ₹ 2000. But, 5 students failed to attend the picnic and thus the cost for food for each member increased by ₹ 20. How many students attended the picnic and how much did each student pay for the food?
Advertisements
Solution
Let x be the number of students who planned a picnic.
∴ Original cost of food for each member =Rs`2000/x`
Five students failed to attend the picnic So `(x-5)` students attended the picnic.
∴ New cost of food for each member =` Rs 200/(x-5)`
According of the given condition,
`Rs 2000/(x-5)-Rs2000/x=Rs 20`
⇒`(2000x-2000x+10000)/(x(x-5))=20`
⇒`10000/(x^2-5x)=20`
⇒`x^2-5x=500`
⇒`x^2-55x-500=0`
⇒`x^2-25x+20x-500=0`
⇒`x(x-25)+20(x-25)=0`
⇒`(x-25)(x+20)=0`
⇒`x-25=0 or x+20=0`
⇒`x=25 or x=-20`
∴` x=25` (Number of students cannot
be negative)
Number of students who attended the picnic `=x-5=23-5=20`
Amount paid by each student for the food =` Rs 2000/((25-5))=Rs2000/20=Rs100`
