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Question
Solve `x/3 + 3/(6 - x) = (2(6 + x))/15; (x ≠ 6)`
Sum
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Solution
`x/3 + 3/(6 - x) = (2(6 + x))/15`
`=> (x(6 - x) + 3 xx 3)/(3(6 - x)) = (12 + 2x)/15`
`=> (x(6 - x^2 + 9))/(6 - x) = (12 + 2x)/15`
= 30x − 5x2 + 45 = 72 − 2x2
= 3x2 − 30x + 27 = 0
= x2 − 10x + 9 = 0
= x2 − 9x − x + 9 = 0
= x(x − 9) − 1(x − 9) = 0
= (x − 9) (x − 1) = 0
= x − 9 = 0 or x − 1 = 0
= x = 9 or x = 1
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