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Question
Solve the inequation given below. Write the solution set and represent it on the number line:
`(-x)/3 ≤ x/2 - 1 1/3 < 1/6, x ∈ R`
Sum
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Solution
Given,
`(-x)/3 ≤ x/2 - 1 1/3 < 1/6`
Solving L.H.S. of the inequation,
⇒ `-x/2 ≤ x/2 - 1 1/3`
⇒ `-x/3 - x/2 ≤ -4/3`
⇒ `(-2x - 3x)/6 ≤ -4/3`
⇒ `(-5x)/6 ≤ -4/3`
⇒ `(5x)/6 ≥ -4/3`
⇒ `x ≥ 4/3 xx 6/5`
⇒ `x ≥ 8/5`
⇒ x ≥ 1.6 ...(1)
Solving R.H.S. of the inequation,
⇒ `x < d 9/6 xx 2`
⇒ x < 3 ...(2)
⇒ 2x – 131 < 61
⇒ 2x – 34 < 61
⇒ 2x < 61 + 34
⇒ 2x < 61 + 8
⇒ 2x < 69
⇒ x < 69 × 2
⇒ x < 3 ...(2)
From (1) and (2) we get,
⇒ 1.6 ≤ x < 3
Since, x ∈ R
Hence, solution set = {x : 1.6 ≤ x < 3, x ∈ R}.
Solution on the number line is:

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