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Solve the following equation by factorisation method: ((4x – 3)/(2x + 1)) – 10((2x + 1)/(4x – 3)) = 3, x ≠ –1/2, 3/4

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Questions

Solve the following equation by factorisation method:

`((4x - 3)/(2x + 1)) - 10((2x + 1)/(4x - 3)) = 3, x ≠ -1/2, 3/4`

Solve the following quadratic equation:

`((4x - 3)/(2x + 1)) - 10((2x + 1)/(4x - 3)) = 3, x ≠ (-1)/2, 3/4` 

Sum
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Solution

Given:

`((4x - 3)/(2x + 1)) - 10((2x + 1)/(4x - 3)) = 3`

Putting `(4x - 3)/(2x + 1) = y`, we get: 

`y - 10/y = 3` 

⇒ `(y^2 - 10)/y = 3` 

⇒ y2 – 10 = 3y   ...[On cross multiplying] 

⇒ y2 – 3y – 10 = 0 

⇒ y2 – (5 – 2)y – 10 = 0 

⇒ y2 – 5y + 2y – 10 = 0 

⇒ y(y – 5) + 2(y – 5) = 0 

⇒ (y – 5)(y + 2) = 0 

⇒ y – 5 = 0 or y + 2 = 0 

⇒ y = 5 or y = –2 

Case I: 

If y = 5, we get: 

`(4x - 3)/(2x + 1) = 5`  

⇒ 4x – 3 = 5(2x + 1)   ...[On cross multiplying] 

⇒ 4x – 3 = 10x + 5 

⇒ –6x = 8 

⇒ `-6x=8` 

⇒ `x = 8/6` 

⇒ `x = -4/3` 

Case II: 

If y = –2, we get: 

`(4x - 3)/(2x + 1) = 2` 

⇒ 4x – 3 = –2(2x + 1) 

⇒ 4x – 3 = –4x – 2 

⇒ 8x = 1 

⇒ `x = 1/8` 

Hence, the roots of the equation are `-4/3` and `1/8`.

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Chapter 5: Quadratic equations - Exercise 5B [Page 65]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic equations
Exercise 5B | Q 27. | Page 65
R.S. Aggarwal Mathematics [English] Class 10
Chapter 4 Quadratic Equations
EXERCISE 4A | Q 67. | Page 184
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