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Question
Solve the following differential equation:
`("d"y)/("d"x) = sqrt((1 - y^2)/(1 - x^2)`
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Solution
The equation can be written as
`("d"y)/sqrt(1 - y^2) = ("d"x)/sqrt(1 - x^2)`
Taking Integration on both sides, we get
`int ("d"y)/sqrt(1 - y^2) = int ("d"x)/sqrt(1 - x^2)`
sin–1y = sin–1x + C
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