Question

Solve `sqrt3x^2-2sqrt2x-2sqrt3=0` 

 

Answer 1

`sqrt3x^2-2sqrt2x-2sqrt3=0`  

⇒`sqrt3^2-3sqrt2x+sqrt2x-2sqrt3=0` 

⇒`sqrt3x(x-sqrt6)+sqrt2 (x-sqrt6)=0` 

⇒`(x-sqrt6) (sqrt3+sqrt2)=0` 

⇒`x-sqrt6=0  or  sqrt3x+sqrt2=0` 

⇒`x=sqrt6  or x=-sqrt2/sqrt3=-sqrt6/3` 

Hence,` sqrt6 and -sqrt6/3`  are the roots of the given equation.