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Question
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2°C. The percentage association of solute A in water is ______.
(Given: Molar mass of A = 93 g mol−1, molal depression constant of water is 1.86 K kg rnol−1)
Options
50%
60%
70%
80%
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Solution
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2°C. The percentage association of solute A in water is 80%.
Explanation:
Given: Mass of solute A = 0.7 g
Molar mass of A = 93 g/mol
Mass of water = 42.0 g = 0.042 kg
Depression in freezing point ΔTf = 0.2°C
Kf = 1.86 K kg/mol
Solute A associates:
Moles of solute A (n) = `0.7/93` = 0.00753 mol
Molality (m) = `0.00753/0.042` = 0.1793 mol/kg
ΔTf = i Kf m
0.2 = i × 1.86 × 0.1793
`i = 0.2/(1.86 xx 0.1793)`
i = 0.602
For the association of n particles to 1, the van’t Hoff factor:
`i = 1 - alpha (1 - 1/n)`
Assume dimerization (n = 2)
0.602 = `1 - alpha(1 - 1/2)`
0.602 = `1 - alpha/2`
`alpha/2` = 1 − 0.602
`alpha/2` = 0.398
α = `0.398/2`
= 0.796
≈ 80%
