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Solid ammonium dichromate decomposes as: (NHA4)A2CrA2OA7⟶NA2+CrA2OA3+4HA2O If 63 g of ammonium dichromate decomposes. Calculate the volume of N2 evolved at STP. - Chemistry

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Question

Solid ammonium dichromate decomposes as:

\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]

If 63 g of ammonium dichromate decomposes. Calculate the volume of N2 evolved at STP.

Numerical
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Solution 1

Solid ammonium dichromate decomposes as:

\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]

252 g of ammonium dichromate gives 22.4 dm3 of N2

63 g of ammonium dichromate gives `(63 xx 22.4)/252`

= 5.6 L

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Solution 2

The volume of N2 evolved at STP = `22.4/4`

= 5.6 litres

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