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Question
Simplify the following:
`"i"^59 + 1/"i"^59`
Sum
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Solution
`"i"^59 + 1/"i"^59 = "i"^(4(14) + 3) + "i"/("i"^(4(14) + 3)`
= `"i"^3 + 1/"i"^3`
= `- "i" + (1 xx "i")/(- "i" xx "i")`
= – i + i
= 0
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Introduction to Complex Numbers
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