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Show that the Vectors → a = 3 ^ I − 2 ^ J + ^ K , → B = ^ I − 3 ^ J + 5 ^ K , → C = 2 ^ I + ^ J − 4 ^ K Form a Right-angled Triangle.

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Question

Show that the vectors \[\vec{a} = 3 \hat{i} - 2 \hat{j} + \hat{k} , \vec{b} = \hat{i} - 3 \hat{j} + 5 \hat{k} , \vec{c} = 2 \hat{i} + \hat{j} - 4 \hat{k}\] form a right-angled triangle. 

Sum
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Solution

\[\text{ Let   ABC  be the given triangle and }\]
\[ \vec{AC} = \vec{b} = \hat{i} - 3 \hat{j} + 5 \hat{k} \]
\[ \vec{CB} = \vec{a} = 3 \hat{i} - 2 \hat{j} + \hat{k} \]
\[ \vec{AB} = \vec{c} = 2 \hat{i} + \hat{j} - 4 \hat{k} \]
\[ \vec{a} . \vec{b} = 3 + 6 + 5 = 14\]
\[ \vec{b} . \vec{c} = 2 - 3 - 20 = - 21\]
\[ \vec{c} . \vec{a} = 6 - 2 - 4 = 0\]
\[\text{ So }, \vec{AB} \text{ is perpendicular to } \vec{CB} . \]
\[\text{ Thus }, ∆ABC\text{ is a right-angled triangle. }\]

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Chapter 23: Scalar Or Dot Product - Exercise 24.1 [Page 31]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 23 Scalar Or Dot Product
Exercise 24.1 | Q 19 | Page 31

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