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Question
Show that the following points are the vertices of a rectangle:
A(4, 2), В(0, –4), С(–3, –2), D(1, 4)
Sum
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Solution
Given: A(4, 2), B(0, –4), C(–3, –2), D(1, 4).
Step-wise calculation:
1. Compute side vectors:
AB = B – A
= (0 – 4, –4 – 2)
= (–4, –6)
BC = C – B
= (–3 – 0, –2 – (–4))
= (–3, 2)
CD = D – C
= (1 – (–3), 4 – (–2))
= (4, 6)
DA = A – D
= (4 – 1, 2 – 4)
= (3, –2)
2. Opposite sides are equal and parallel:
CD = –AB (CD = (4, 6), AB = (–4, –6))
⇒ AB || CD and |AB| = |CD|.
DA = –BC (DA = (3, −2), BC = (–3, 2))
⇒ BC || DA and |BC| = |DA|.
Therefore, ABCD is a parallelogram.
3. Check for a right-angle dot product of adjacent sides:
AB · BC = (–4)(–3) + (–6)(2)
= 12 – 12
= 0
A zero dot product means AB ⟂ BC.
ABCD is a parallelogram with one right angle, hence it is a rectangle.
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Chapter 19: Co-ordinate Geometry: An Introduction - Exercise 19D [Page 404]
