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Shanker invests ₹ 48000 for 3 years at 5% per annum compound interest. Find i. the interest for the first year. ii. the amount at the end of second year. iii. the interest for third year. - Mathematics

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Question

Shanker invests ₹ 48000 for 3 years at 5% per annum compound interest. Find

  1. the interest for the first year. 
  2. the amount at the end of second year.
  3. the interest for third year.
Sum
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Solution

Given:

  • Principal (P) = ₹ 48,000
  • Rate of Interest (R) = 5% per annum (compounded annually)
  • Time (T) = 3 years

Step-wise calculation:

i. Interest for the first year

For the first year, interest is simple because it is on the original principal.

Interest1 = `(P xx R xx 1)/100`

= `(48000 xx 5 xx 1)/100`

=  ₹ 2400

ii. Amount at the end of the second year

Amount after first year:

A1 = P + Interest1

= 48000 + 2400

= ₹ 50400

For the second year, interest is calculated on the new principal (A1): 

Interest2 = `(50400 xx 5 xx 1)/100`

Interest2 = ₹ 2520

Amount at the end of second year: 

A2 = A1 + Interest2

= 50400 + 2520

= ₹ 52920

iii. Interest for the third year

Now interest will be on the amount at the end of the second year:

Interest3 = `(52920 xx 5 xx 1)/100`

Interest3 = ₹ 2646

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Chapter 2: Compound Interest - Exercise 2A [Page 42]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest
Exercise 2A | Q 6. | Page 42
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