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Select the correct option from the given alternatives : If α + β + γ = π then the value of sin2α + sin2β – sin2γ is equal to …...... - Mathematics and Statistics

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Question

Select the correct option from the given alternatives :

If α + β + γ = π then the value of sin2α + sin2β – sin2γ is equal to …......

Options

  • 2 sin α 

  • 2 sin α cos β sin γ

  • 2 sin α sin β cos γ

  • 2 sin α sin β sin γ

MCQ
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Solution

2 sin α sin β cos γ

Explanation:

`sin^2alpha + sin^2 beta - sin^2γ`

= `(1 - cos2alpha)/2 + (1 - cos2beta)/2 - sin^2γ`

= `1 - 1/2(cos2alpha + cos2beta) - 1 + cos^2γ`

= `-1/2 xx 2cos(alpha + beta)cos(alpha - beta) + cos^2γ`

= cos γ cos (α – β) + cos  ...[∵ α + β + γ = π]

= cos γ [cos (α – β) + cos γ]

= cos γ [cos (α – β) – cos (α + β)]

= 2 sin α sin β cos γ

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Chapter 3: Trigonometry - 2 - Miscellaneous Exercise 3 [Page 57]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q I. (vii) | Page 57
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