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Question
Saline hydrides are known to react with water violently producing fire. Can CO2, a well-known fire extinguisher, be used in this case? Explain.
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Solution
Saline hydrides (i.e., NaH, LiH, etc.) react with water to form a base and hydrogen gas. The chemical equation used to represent the reaction can be written as:
\[\ce{NaH_{(s)} + H_2O_{(aq)} -> NaOH_{(aq)} + H_{2(g)}}\]
The reaction is violent and produces fire.
Instead of smothering the fire, the hot metal hydride will act as a reducing agent and reduce the CO2.
This reaction produces flammable products, including more hydrogen gas, which further fuels the fire. For example, the reaction between sodium hydride and carbon dioxide can be represented as:
\[\ce{2NaH + CO2 -> Na2CO3 + H2}\]
These fires cannot be extinguished with agents like water or CO2 because the metals are so reactive that they can steal oxygen from the extinguishing agent, intensifying the fire.
RELATED QUESTIONS
Arrange the following:
NaH, MgH2 and H2O in order of increasing reducing property.
How can saline hydrides remove traces of water from organic compounds?
What do you expect the nature of hydrides is, if formed by elements of atomic numbers 15, 19, 23 and 44 with dihydrogen? Compare their behaviour towards the water.
Which of the following hydrides is electron-precise hydride?
Which of the following statements about hydrogen are correct?
(i) Hydrogen has three isotopes of which protium is the most common.
(ii) Hydrogen never acts as cation in ionic salts.
(iii) Hydrogen ion, \[\ce{H+}\], exists freely in solution.
(iv) Dihydrogen does not act as a reducing agent.
Which of the following statements is correct?
(i) Elements of group 15 form electron deficient hydrides.
(ii) All elements of group 14 form electron precise hydrides.
(iii) Electron precise hydrides have tetrahedral geometries.
(iv) Electron rich hydrides can act as Lewis acids.
NaH is an example of ______.
