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Question
Roy starts a business with Rs. 10000, Shikha joins him after 2 months with 20% more investment than Roy, after 2 months Tariq joins him with 40% less than Shikha. If the profit earned by them at the end of the year is equal to twice the difference between the investment of Roy and ten times the investment of Tariq. Find the profit of Roy?
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Solution
Given, Roy starts the business with ₹ 10,000.
Shikha joins him after 2 months with 20% more investment than Roy.
∴ Shikha’s investment = `10,000 + (10,000 xx 20/100)`
= ₹ 12,000
Tariq joins after two more months with an investment 40% less than Shikha.
∴ Tariq’s investment = `12,000 − (12,000 xx 40/100)`
= ₹ 7,200
Now, the profit will be shared in the proportion of products of capital and respective periods in months.
i.e. 10,000 × 12 : 12,000 × 10 : 7,200 × 8
i.e. in the proportion,
25 : 25 : 12 …(i) [Dividing throughout by 4,800]
Given that, profit at the end of the year = twice of the difference between the investment of Roy and ten times the investment of Tariq.
∴ Profit = 2 [(10 × 7,200) – 10,000]
= 2[72,000 − 10,000]
= 2 × 62,000
= ₹ 1,24,000
∴ Roy’s share of profit = `25/62 xx 1,24,000` ......[From(i)]
= ₹ 50,000/-
