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Question
Ranjan invests ₹ 15,360 for 2 years at a certain rate compounded annually. At the end of one year, it amounts to ₹ 16,320. Calculate
- the rate of interest
- the amount at the end of second year.
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Solution
Given:
- Principal (P) = ₹ 15,360
- Amount at the end of the first year (A1) = ₹ 16,320
- Time (n) = 1 year for the first year, and 2 years in total.
i. Rate of interest (R):
We can use the compound interest formula for the first year to find the rate of interest:
`A = P(1 + R/100)^n`
For the first year:
`A_1 = P(1 + R/100)`
Substituting the known values:
`16,320 = 15,360(1 + R/100)`
Now solve for R:
`(16,320)/(15,360) = 1 + R/100`
⇒ `1.06 = 1 + R/100`
⇒ `R/100 = 0.06`
⇒ R = 6%
So, the rate of interest is 6%.
ii. Amount at the end of the second year:
Now, we calculate the amount at the end of the second year using the formula:
`A = P(1 + R/100)^2`
Substituting the known values:
`A = 15,360(1 + 6/100)^2`
= 15,360 × 1.062
= 15,360 × 1.1236
A = ₹ 17,340
So, the amount at the end of the second year is ₹ 17,340.
