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Rahul borrows ₹ 25000 for 2 years and the rates of interest for two successive years are 10% and 8% respectively. If he repays ₹ 7500 at the end of first year - Mathematics

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Question

Rahul borrows ₹ 25000 for 2 years and the rates of interest for two successive years are 10% and 8% respectively. If he repays ₹ 7500 at the end of first year, find the amount due at the end of second year.

Sum
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Solution

Given:

  • Rahul borrows ₹ 25000 for 2 years.
  • Rate of interest for first year = 10%
  • Rate of interest for second year = 8%
  • He repays ₹ 7500 at the end of the first year.
  • We need to find the amount due at the end of the second year.

Step-wise calculation:

1. Calculate the amount after the first year including interest:

Interest for 1st year = `(25000 xx 10 xx 1)/100` = ₹ 2500

Amount after 1st year = 25000 + 2500 = ₹ 27500

2. Subtract the repayment made at the end of the first year from the amount due:

Balance after repayment = 27500 – 7500 = ₹ 20000

3. Calculate the interest for the second year on the balance:

Interest for 2nd year = `(20000 xx 8 xx 1)/100` = ₹ 1600

4. Calculate the amount due at the end of the second year:

Amount due at end of 2nd year = 20000 + 1600 = ₹ 21600

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Chapter 2: Compound Interest - Exercise 2A [Page 43]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest
Exercise 2A | Q 16. | Page 43
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