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Prove the following: sin3(π+x)sec2(π-x)tan(2π-x)cos2(π2+x)sin(π-x)cosec2-x = tan3x - Mathematics and Statistics

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Question

Prove the following:

`(sin^3(pi + x)sec^2(pi - x)tan(2pi - x))/(cos^2(pi/2 + x)sin(pi - x)"cosec"^2 - x)` = tan3x

Sum
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Solution

L.H.S. = `(sin^3(pi + x)sec^2(pi - x)tan(2pi - x))/(cos^2(pi/2 + x)sin(pi - x)"cosec"^2 (- x))` 

=  `([sin(pi + x)]^3 [sec(pi - x)]^2 tan(2pi - x))/([cos(pi/2 + x)]^2 sin(pi - x)*(-"cosec")^2`

= `((-sinx)^3(-secx)^2(-tanx))/((-sinx)^2*sinx*"cosec"^2x)`

= `((-sin^3x)*sec^2x*(-tanx))/(sin^2x*sinx*1/sin^2x)`

= `(sin^3x*sec^2x*tanx)/sinx`

= `sin^2x*1/cos^2x tanx`

= tan2x.tanx

= tan3x

= R.H.S.

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Trigonometric Functions of Allied Angels
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Chapter 3: Trigonometry - 2 - Exercise 3.2 [Page 42]

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