Advertisements
Advertisements
Question
Prove that two different circles cannot intersect each other at more than two points.
Advertisements
Solution
Suppose two circles intersect in three points A,B,C,
Then A,B,C are non-collinear. So, a unique circle passes through these three points. This is contradiction to the face that two given circles are passing through A,B,C. Hence, two circles cannot intersect each other at more than two points.
APPEARS IN
RELATED QUESTIONS
Points A(–1, y) and B(5, 7) lie on a circle with centre O(2, –3y). Find the values of y. Hence find the radius of the circle.
Find the length of a tangent drawn to a circle with radius 5cm, from a point 13 cm from the center of the circle.
In fig.. O is the center of the circle and BCD is tangent to it at C. Prove that ∠BAC +
∠ACD = 90°
In Figure 3, a circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm. Find the length of the side AD.

In the given figure, if ∠BAC = 60° and ∠BCA = 20°, find ∠ADC.

In the given figure, two tangents AB and AC are drawn to a circle with centre O such that ∠BAC = 120°. Prove that OA = 2AB.

In following fig. ABC is an equilateral triangle . A circle is drawn with centre A so that ot cuts AB and AC at M and N respectively. Prove that BN = CM.

Use the figure given below to fill in the blank:
If PQ is 8 cm long, the length of RS = ________

Draw a circle of radius 6 cm. In the circle, draw a chord AB = 6 cm.
(i) If O is the center of the circle, join OA and OB.
(ii) Assign a special name to ∆AOB
(iii) Write the measure of angle AOB.
Circles with centres A, B and C touch each other externally. If AB = 3 cm, BC = 3 cm, CA = 4 cm, then find the radii of each circle.
