Advertisements
Advertisements
Question
Prove that following numbers are irrationals:
\[5\sqrt{2}\]
Numerical
Advertisements
Solution
Let us assume that \[5\sqrt{2}\] is rational .Then , there exist positive co primes a and bsuch that
\[5\sqrt{2}\]`=a/b`
`sqrt2=a/b-5`
`sqrt5=(a-5b)/b`
`sqrt2` is a rational which is a contradication
shaalaa.com
Is there an error in this question or solution?
