Advertisements
Advertisements
Question
Prove that cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1.
Advertisements
Solution
LHS = cos θ sin (90° - θ) + sin θ cos (90° - θ)
= cos θ. cos θ + sin θ. sin θ
= cos2θ + sin 2θ
= 1
= RHS
Hence proved.
RELATED QUESTIONS
If cos θ + cot θ = m and cosec θ – cot θ = n, prove that mn = 1
Prove the following identities:
cosec4 A – cosec2 A = cot4 A + cot2 A
If 2 sin A – 1 = 0, show that: sin 3A = 3 sin A – 4 sin3 A
Prove the following identity :
`(1 + tan^2θ)sinθcosθ = tanθ`
Find the value of sin 30° + cos 60°.
Prove the following identities:
`1/(sin θ + cos θ) + 1/(sin θ - cos θ) = (2sin θ)/(1 - 2 cos^2 θ)`.
Prove that `[(1 + sin theta - cos theta)/(1 + sin theta + cos theta)]^2 = (1 - cos theta)/(1 + cos theta)`
Which is not correct formula?
Prove that sec2θ – cos2θ = tan2θ + sin2θ.
Prove that `(cot A)/(1 - tan A) + (tan A)/(1 - cot A) = 1 + tan A + cot A = sec A . "cosec" A + 1`.
