This proves that the product of refractive indices in a closed loop equals one.
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Question
Prove that 1n2 × 2n3 × 3n1 = 1.
Theorem
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Solution
The proof that 1n2 × 2n3 × 3n1 = 1 is given by considering the refractive indices between three media: 1, 2, and 3.
Using Snell’s law:
`""_1n_2 = (sin i_1)/(sin r_1), ""_2n_3 = (sin r_1)/(sin r_2), ""_3n_1 = (sin r_2)/(sin i_1)`
Multiplying these three indices:
`""_1n_2 xx ""_2n_3 xx ""_3n_1 = (sin i_1)/(sin r_1) xx (sin r_1)/(sin r_2) xx (sin r_2)/(sin i_1) = 1`
Hence, 1n2 × 2n3 × 3n1 = 1
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