Advertisements
Advertisements
Question
Protons can be accelerated in particle accelerators. Calculate the wavelength (in Å) of such accelerated proton moving at 2.85 × 108 ms−1 (the mass of proton is 1.673 × 10−27 Kg).
Advertisements
Solution
Given v = 2.85 × 108 ms–1
mp = 1.673 × 10–27 Kg
λ = `"h"/"mv"`
= `(6.626 xx 10^-34 "kgm"^2 "s"^-1)/(1.673 xx 10^-27 "kg" xx 2.85 xx 10^8 "ms"^-1)`
λ = 1.389 × 10–15
λ = 1.389 × 10–15 Å ......[∵ 1 Å = 10–10 m]
APPEARS IN
RELATED QUESTIONS
The energy of light of wavelength 45 nm is
Based on equation E = `-2.178 xx 10^(-18) "J" ("z"^2/"n"^2)`, certain conclusions are written. Which of them is not correct?
Which of the following pairs of d-orbitals will have electron density along the axes?
Two electrons occupying the same orbital are distinguished by __________.
What is the maximum numbers of electrons that can be associated with the following set of quantum numbers?
n = 3, l = 1 and m = –1
Electron density in the yz plane of 3dxy orbital is
Which quantum number reveal information about the shape, energy, orientation and size of orbitals?
How many orbitals are possible for n = 4?
How many radial nodes for 2s, 4p, 5d and 4f orbitals exhibit? How many angular nodes?
The stabilisation of a half-filled d-orbital is more pronounced than that of the p-orbital why?
