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Question
Predict whether the following reaction is feasible under standard conditions or not:
\[\ce{Zn_{(s)} + Cu{^{2+}_{(aq)}} -> Zn{^{2+}_{(aq)}} + Cu_{(s)}}\]
Given that `E_(Zn^(2+)//Zn)^circ` = −0.76 volts and `E_(Cu^(2+)//Cu)^circ` = +0.34 volts.
Numerical
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Solution
Given: `E_(Zn^(2+)//Zn)^circ` = −0.76 volts
`E_(Cu^(2+)//Cu)^circ` = +0.34 volts
Anode: Zn is oxidised to Zn2+.
Cathode: Cu2+ is reduced to Cu.
We know that
`E_"cell"^circ = E_"cathode"^circ - E_"anode"^circ`
`E_"cell"^circ` = (+0.34 V) − (−0.76 V)
`E_"cell"^circ` = +1.10 V
Since the standard potential is positive (`E_"cell"^circ` = +1.10 V), the reaction is feasible and will occur spontaneously under standard conditions.
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Chapter 3: Electrochemistry - REVIEW EXERCISES [Page 148]
