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Question
Predict the products of electrolysis of a dilute aqueous solution of sulphuric acid using inert electrodes.
Very Short Answer
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Solution
In dilute aqueous solution, sulfuric acid ionizes as:
\[\ce{H2SO4 -> 2H^{+}_{ (aq)} + SO^{2-}_{4 (aq)}}\]
Electrolysis takes place as:
At cathode: \[\ce{2H{^{+}_{(aq)}} + 2e- -> H2_{(g)}}\]
At anode: \[\ce{H2P_{(l)} -> 1/2 O2_{(g)} + 2H{^{+}_{(aq)}} + 2e-}\]
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