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Question
Predict the number of unpaired electrons in [Fe(H2O)6]3+ and [Fe(CN)6]3− based on crystal field theory.
Very Short Answer
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Solution
For [Fe(H2O)6]3+, \[\ce{t^3_{2g} eg^2}\]
No. of unpaired electrons = 5
for [Fe(CN)6]3−, \[\ce{t^5_{2g} eg^0}\]
No. of unpaired electrons = 1
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