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Question
PQRS is a square. ΔOPQ is equilateral. The measure of angle a is ______.

Options
80°
70°
75°
60°
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Solution
PQRS is a square. ΔOPQ is equilateral. The measure of angle a is 75°.
Explanation:

Step 1: Use the properties of a square and an equilateral triangle
Given that PQRS is a square, all its sides are equal in length PQ = PS. All interior angles of a square are 90°, so ∠SPQ = 90°.
Given that ΔOPQ is an equilateral triangle, all its sides are equal PQ = PO. All interior angles of an equilateral triangle are 60°, so ∠OPQ = 60°.
Step 2: Identify the isosceles triangle
Since PQ = PS from the square and PQ = PO from the equilateral triangle, it follows that PS = PO. This means that ΔSPO is an isosceles triangle.
First, find the measure of the angle at the vertex P in ΔSPO.
∠SPO = ∠SPQ – ∠OPQ
= 90° – 60°
= 30°
In an isosceles triangle, the base angles are equal. The base angles are ∠PSO and ∠POS.
Let’s assume the angle ‘a’ in the problem is ∠PSO. The sum of angles in a triangle is 180°.
∠SPO + ∠PSO + ∠POS = 180°
30° + a + a = 180°
30° + 2a = 180°
Step 4: Solve for ‘a’
Subtract 30° from both sides of the equation:
2a = 180° – 30°
2a = 150°
Divide by 2 to find the value of a:
a = `150^circ/2`
a = 75°
