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Question
PQRS is a rectangle. PA = 16 cm, AQ = 9 cm and QR = 12 cm.

- Find the lengths of AS and AR.
- Prove that ∠SAR = 90°.
Sum
Theorem
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Solution
PQRS is a rectangle.
PA = 16, AQ = 9 cm
PQ = PA + AQ
= 16 + 9
= 25 cm
QR = 12 cm
PS = QR = 12 cm
SR = PQ = 25 cm
(i) Find the lengths of AS and AR.
In △APS (right-angled at P):
AS2 = AP2 + PS2
= 162 + 122
= 256 + 144
= 400
AS = `sqrt400`
AS = 20 cm
In △AQR (right-angled at Q):
AR2 = AQ2 + QR2
= 92 + 122
= 81 + 144
= 225
AR = `sqrt225`
AR = 15 cm
(ii) Prove that ∠SAR = 90°:
Consider △SAR: its sides are AS = 20, AR = 15, SR = 25.
Check Pythagoras theorem,
AS2 + AR2
= 202 + 152
= 400 + 225
= 625
SR2 = 252 = 625
Since AS2 + AR2 = SR2
By the converse of Pythagoras theorem, triangle SAR is right-angled at A.
So, ∠SAR = 90°
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