Question

One mole of PCl₅ is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, Calculate the value of equilibrium constant.

Answer 1

Given that,

`["PCl"_5]_"initial" = (1 "mole")/(1 "dm"^3)`

[Cl₂]_eq = 0.6 mole dm^-3 

\[\ce{PCl5 <=> PCL3 + Cl2}\]

[PCl₃]_eq = 0.6 mole dm^-3

[PCl₅]_eq = 0.4 mole dm^-3 

`therefore "K"_"C" = (["PCl"_3]["Cl"_2])/(["PCl"_5])`

`= (0.6 xx 0.6)/0.4`

= 0.9 mole dm^-3