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Question
One card is drawn from a pack of 52 cards. The probability that it is the card of a king or spade is
Options
1/26
3/26
4/13
3/13
MCQ
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Solution
4/13
If A and B denote the events of drawing a king and a spade card, respectively, then event A consists of four sample points, whereas event B consists of 13 sample points.
Thus,
\[P\left( A \right) = \frac{4}{52}\] and \[P\left( B \right) = \frac{13}{52}\]
The compound event (A ∩ B) consists of only one sample point, king of spade.
So,
So,
\[P\left( A \cap B \right) = \frac{1}{52}\]
By addition theorem , we have:
P (A ∪ B) = P(A) + P (B) − P (A ∩ B)
= \[\frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}\]
P (A ∪ B) = P(A) + P (B) − P (A ∩ B)
= \[\frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}\]
Hence, the probability that the card drawn is either a king or a spade is given by \[\frac{4}{13}\] .
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