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Question
On using elementary row operation R1 → R1 – 3R2 in the following matrix equation: `[(4, 2),(3, 3)] = [(1, 2),(0, 3)] [(2, 0),(1, 1)]`, we have: ______.
Options
`[(-5, -7),(3, 3)] = [(1, -7),(0, 3)] [(2, 0),(1, 1)]`
`[(-5, -7),(3, 3)] = [(1, 2),(0, 3)] [(-1, -3),(1, 1)]`
`[(-5, -7),(3, 3)] = [(1, 2),(1, -7)] [(2, 0),(1, 1)]`
`[(4, 2),(-5, -7)] = [(1, 2),(-3, -3)] [(2, 0),(1, 1)]`
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Solution
On using elementary row operation R1 → R1 – 3R2 in the following matrix equation: `[(4, 2),(3, 3)] = [(1, 2),(0, 3)] [(2, 0),(1, 1)]`, we have: `[(-5, -7),(3, 3)] = [(1, -7),(0, 3)] [(2, 0),(1, 1)]`.
Explanation:
We have, `[(4, 2),(3, 3)] = [(1, 2),(0, 3)] [(2, 0),(1, 1)]`
Using elementary row transformation R1 → R1 – 3R2
`[(-5, -7),(3, 3)] = [(1, -7),(0, 3)] [(2, 0),(1, 1)]`
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