Advertisements
Advertisements
Question
On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.
(a) \[\ce{C (graphite) + O2 (g) -> CO2 (g) ; ∆_rH = xkJ mol^{-1}}\]
(b) \[\ce{C (graphite) + 1/2 O2 (g) -> CO (g) ; ∆_rH = ykJ mol^{-1}}\]
(c) \[\ce{CO (g) + 1/2 O2 (g) -> CO2 (g) ; ∆_r H = zkJ mol^{-1}}\]
Options
z = x + y
x = y – z
x = y + z
y = 2z – x
Advertisements
Solution
x = y + z
Explanation:
When we add equations (b) and (c) we will get equation (a) hence, Algebraic sum of y and z will give x, x = y + z.
APPEARS IN
RELATED QUESTIONS
Heat of combustion is always ___________.
Molar heat of vapourisation of a liquid is 4.8 kJ mol–1. If the entropy change is 16 J mol–1 K–1, the boiling point of the liquid is
Define molar heat capacity.
Write the unit of molar heat capacity.
What are state and path functions? Give two examples.
\[\ce{∆_f U^Θ}\] of formation of \[\ce{CH4 (g)}\] at certain temperature is – 393 kJ mol–1. The value of \[\ce{∆_f H^Θ}\] is ______.
The standard molar entropy of \[\ce{H2O (l)}\] is 70 JK–1 mol–1. Will the standard molar entropy of \[\ce{H2O (s)}\] be more, or less than 70 JK–1 mol–1?
The molar enthalpy of vapourisation of acetone is less than that of water. Why?
If the combustion of 1g of graphite produces 20.7 kJ of heat, what will be molar enthalpy change? Give the significance of sign also.
Derive the relationship between ∆H and ∆U for an ideal gas. Explain each term involved in the equation.
The molar heat of formation of NH4NO3 (s) is −367.54 kJ and those of N2O (g), H2O (l) are 81.46 and −285.8 kJ respectively at 25°C and atmosphere pressure. The difference of ΔH and ΔE of the reaction \[\ce{NH4NO3(s) -> N2O (g) + 2H2O (l)}\] is ______ kJ.
A cylinder of gas supplied by Bharat Petroleum is assumed to contain 14 kg of butane. If a normal family requires 20,000 kJ of energy per day for cooking, butane gas in the cylinder last for ______ Days. (Δ Hc of C4 H10 = - 2658 JK per mole)
