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Question
Obtain all other zeroes of (x4 + 4x3 – 2x2 – 20x – 15) if two of its zeroes are `sqrt(5)` and `-sqrt(5)`.
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Solution
The given polynomial is f(x) = x4 + 4x3 – 2x2 – 20x – 15.
Since `(x - sqrt(5))` and `(x + sqrt(5))` are the zeroes of f(x) it follows that each one of `(x - sqrt(5))` and `(x + sqrt(5))` is a factor of f(x).
Consequently, `(x - sqrt(5)) (x + sqrt(5)) = (x^2 - 5)` is a factor of f(x).
On dividing f(x) by (x2 – 5), we get:
`x^2 - 5")"overline(x^4 + 4x^3 - 2x^2 - 20x - 15)"("2x^2 - 3x + 1`
x4 – 5x2
– +
4x3 + 3x2 – 20x – 15
4x3 – 20
– +
3x2 – 15
3x2 – 15
– +
x
f(x) = 0
⇒ x4 + 4x3 – 7x2 – 20x – 15 = 0
⇒ (x2 – 5) (x2 + 4x + 3) = 0
⇒ `(x - sqrt(5)) (x + sqrt(5)) (x + 1) (x + 3) = 0`
⇒ x = `sqrt(5)` or x = `-sqrt(5)` or x = –1 or x = –3
Hence, all the zeroes are `sqrt(5), -sqrt(5)`, –1 and –3.
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