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Question
O is the in-centre of the ΔABC, if ∠BOC = 116°, then ∠BAC is
Options
42°
62°
58°
52°
MCQ
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Solution
52°
Explanation:
The point of intersection of internal bisectors of a triangle is called in-centre.
∠BOC = `90^circ + (∠A)/2`
⇒ 116° = `90^circ + (∠A)/2`
⇒ `(∠A)/2` = 116° – 90° = 26°
∴ ∠A = 26 × 2 = 52°
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Geometry (Entrance Exam)
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