Advertisements
Advertisements
Question
Numerical Problem.
Density of mercury is 13600 kg m–3. Calculate the relative density.
Advertisements
Solution
Relative Density = `"Density of Mercury"/"Density of water"` at 4°C
R.D. = 13.6
APPEARS IN
RELATED QUESTIONS
The density of gold is 19 g/cm3. Find the volume of 95 g of gold.
What is the mass of 5 m3 of cement of density 3000 kg/m3 ?
What is the density of a substance of mass 100 g and volume 10 cm3 ?
If the relative density of a substance is 7.1, what will be its density in SI units ?
5 kg of material A occupy 20 cm3 whereas 20 kg of materia! B occupy 90 cm3. Which has the greater density : A or B ? Support your answer with calculations.
A body floats in kerosene of density 0.8 x 103 kg/m3 up to a certain mark. If the same body is placed in water of density 1.0 x 103 kg/m3, will it sink more or less ? Give reason for your answer.
A solid of density 900 kg/m3 floats in oil as shown in the given diagram. The oil floats on water of density 1000 kg/m3 as shown. The density of oil kg/m3 could be :
The diagrams represent four measuring cylinders containing liquids. The mass and volume of the liquid in each cylinder are stated. Which two measuring cylinder could contain an identical liquid?
Calculate the average density of the earth in terms of g, G and R
A cube of side 5 cm is immersed in water and then in a saturated salt solution. In which case will it experience a greater buoyant force. If each side of the cube is reduced to 4 cm and then immersed in water, what will be the effect on the buoyant force experienced by the cube as compared to the first case for water. Give a reason for each case.
