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Question

No Question.

Answer in Brief
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Solution

Radius of the bigger sphere = r cm
Radius of smaller spheres = rcm

\[\frac{\text { Volume of bigger sphere }}{\text { Volume of small spheres }} = \frac{\frac{4}{3} \pi r^3}{\frac{4}{3}\pi r_1^3} = \frac{r^3}{r_1^3} = 8\]

\[ \Rightarrow \left( \frac{r}{r_1} \right)^3 = \left( \frac{2}{1} \right)^3 \]

\[ \Rightarrow \left( \frac{r}{r_1} \right) = \left( \frac{2}{1} \right)\]

Hence, r : r= 2 : 1.

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Chapter 14: Surface Areas and Volumes - Exercise 14.5 [Page 91]

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RD Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
Exercise 14.5 | Q 50 | Page 91
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