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Nitrogen and hydrogen react to form ammonia. NA2A(g)+3HA2A(g)⟶2NHA3A(g) If 1000g H2 reacts with 2000g of N2 Will any of the two reactants remain unreacted? If yes, which one and what will be its mass?

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Question

Nitrogen and hydrogen react to form ammonia.

\[\ce{N2_{(g)} + 3H2_{(g)}-> 2NH3_{(g)}}\]

If 1000g H2 reacts with 2000g of N2

Will any of the two reactants remain unreacted? If yes, which one and what will be its mass?

Numerical
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Solution

\[\ce{N2_{(g)} + 3H2_{(g)}-> 2NH3_{(g)}}\]
28g        6g                 34g

28g of nitrogen requires hydrogen = 6g

2000g of nitrogen requires hydrogen = `6/28 × 2000`

= `3000/7`g

So mass of hydrogen left unreacted =`1000-3000/7`

= `4000/7`

= 571.4g of H2

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