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Question
Niobium crystallises in body centred cubic structure. Its density is 8.55 g cm−3 and its atomic mass is 93 g mol−1. (NA = 6.023 × 1023)
What is the edge length of niobium?
Options
314.50 pm
330.56 pm
340.43 pm
346.30 pm
MCQ
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Solution
340.43 pm
Explanation:
Given: Body-centred cubic (bcc) structure ⇒ Z = 2 atoms/unit cell
Density (ρ) = 8.55 g/cm3
Atomic mass (M) = 93 g/mol
Avogadro’s number (NA) = 6.023 × 1023 mol−1
`rho = (Z xx M)/(N_A xx a^3)`
`a^3 = (Z xx M)/(rho xx N_A)`
`a^3 = (2 xx 93)/(6.023 xx 10^23 xx 8.55)`
`a^3 = 186/(51.48765 xx 10^23)`
a3 = 3.612 × 10−23 cm3
a = `(3.612 xx 10^(−23))^(1/3)`
a = 3.4043 × 10−8 cm
a = 340.43 pm
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Notes
The solution given in the textbook is incorrect.
Is there an error in this question or solution?
Chapter 1: Solid State - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 57]
