Question

Nine cards (identical in all respects) are numbered 2 to 10. A card is selected from them at random. Find the probability that the card selected will be an even number and a multiple of 3. 

Answer 1

There are 9 cards from which one card is drawn. 

Total number of elementary events = n(S) = 9 

From numbers 2 to 10, there is one number which is an even number as well as multiple of 3 i.e. 6 

Favorable number of events = n(E) = 1 

Probability of selecting a card with a number which is an even number as well as multiple of 3 = `(n(E))/(n(S)) = 1/9`