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Question
निऑन तथा CO2 के त्रिक बिंदु क्रमशः 24.57 K तथा 216.55 K हैं। इन तापों को सेल्सियस तथा फारेनहाइट मापक्रमों में व्यक्त कीजिए।
Numerical
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Solution
यहाँ TNe = 24.57 K तथा TCO2 = 216.55 K
परन्तु (t + 273.15) = T ⇒ t = (T – 273.15)°C
∴ tNe = TNe – 273.15 = (24.57 – 279.15)°C = -248.58°C
`"t"_("Co"_2) = "T"_("Co"_2)` - 273.15 = (216.55 – 273.15) = -56.6°C
∵ `("F" - 32)/9 = ("T"- 273.15)/5`
`=> "F" = 32 + 9/5 ("T"- 273.15)`
`"F"_"Ne" = 32 + 9/5(24.57 - 273.15)^circ "F"`
= `[32 + (9 xx -248.58)/5]^circ "F"`
= `[32 - ((9 xx 248.58)/5)]^circ "F"`
= `415.44^circ"F"`
`"F"_("CO"_2) = [32 + 9/5 (216.55 - 273.15)]^circ"F" `
= `[32 + 9/5 xx -56.6]^circ"F"`
= `(32 - (9 xx 56.6)/5)^circ"F"`
= 69.88°F
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