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Question
Mx and My denote the atomic masses of the parent and the daughter nuclei respectively in a radioactive decay. The Q-value for a β– decay is Q1 and that for a β+ decay is Q2. If m e denotes the mass of an electron, then which of the following statements is correct?
Options
Q1 = (Mx – My) c2 and Q2 = [Mx – My – 2me]c2
Q1 = (Mx – My) c2 and Q2 = (Mx – My)c2
Q1 = (Mx – My – 2me) c2 and Q2 = (Mx – My + 2 me)c2
Q1 = (Mx – My + 2me) c2 and Q2 = (Mx – My + 2 me)c2
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Solution
Q1 = (Mx – My) c2 and Q2 = [Mx – My – 2me]c2
Explanation:
Q value or energy of nuclear reaction: The energy absorbed or released during a nuclear reaction is known as the Q-value of nuclear reaction.
Q-value = (Mass of reactants – mass of products)c2 Joules
= (Mass of reactants – mass of products) amu
If Q < 0, the nuclear reaction is known as endothermic. (The energy is absorbed in the reaction)
If Q > 0, the nuclear reaction is known as exothermic. (The energy is released in the reaction)
Let the nucleus be ZXA
β– decay is represented as: zXA → z+1AY + –1e0 + `barv` + Q1
Q1 = [mn(zXA) – mn(z+1YA) – me]c2
= [mn(zXA) + Zme – mn(z+1YA) – (Z + 1)me]c2
= [m(zXA) – m(z–1YA)]c2
⇒ Q1 = (Mx – My)c2
β+ decay is represented as: zXA → z–1YA + –1e0 + v + Q2
Q2 = [mn(zXA) – mn(z–1YA) – me]c2
= [mn(zXA) + Zme – mn(z–1YA) – (Z – 1)me – me]c2
= [m(zXA) – m(z–1YA) – 2me]c2
⇒ Q2 = (Mx – My – 2me)c2
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