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Question
Multiply the binomials.
`(3/4 a^2 + 3b^2) and 4(a^2 - 2/3 b^2)`
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Solution
`(3/4 a^2+ 3b^2) xx [4(a^2 - 2/3 b^2)]`
= `(3/4 a^2 + 3b^2) xx (4a^2 - 8/3 b^2)`
= `3/4 a^2 xx (4a^2 - 8/3 b^2) + 3b^2 xx (4a^2 - 8/3 b^2)`
= 3a2 − 2a2b2 + 12b2a2 − 8b4
= 3a4 + 10a2b2 − 8b4
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