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Question
Moment of intertia of a solid sphere about its diameter is 25 kg m2. Calculate its moment of inertia about a tangent.
Numerical
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Solution
Moment of inertia of a solid sphere about its diameter,
Id = `2/5 M R^2`
25 = `2/5 M R^2`
MR2 = `(25 xx 5)/2`
MR2 = `125/2`
∴ `I_"tangent"` = Id + MR2
= `25 + 125/2`
= `175/2`
= 87.5 kg.m2
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