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Question
Match the following:
| Column I | Column II |
| (i) `a/b ÷ a/b` | (a) `(-a)/b` |
| (ii) `a/b ÷ c/d` | (b) –1 |
| (iii) `a/b ÷ (-1)` | (c) 1 |
| (iv) `a/b ÷ (-a)/b` | (d) `(bc)/(ad)` |
| (v) `b/a ÷ (d/c)` | (e) `(ad)/(bc)` |
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Solution
| Column I | Column II |
| (i) `a/b ÷ a/b` | (c) 1 |
| (ii) `a/b ÷ c/d` | (e) `(ad)/(bc)` |
| (iii) `a/b ÷ (-1)` | (a) `(-a)/b` |
| (iv) `a/b ÷ (-a)/b` | (b) –1 |
| (v) `b/a ÷ (d/c)` | (d) `(bc)/(ad)` |
Explanation:
(i) Given, `a/b ÷ a/b = a/b xx b/a = 1` ...`[∵ "Reciprocal of " a/b = b/a]`
(ii) Given, `a/b ÷ c/d = a/b xx d/c = (ad)/(bc)` ...`[∵ "Reciprocal of " c/d = d/c]`
(iii) Given, `a/b ÷ (-1) = a/b xx (-1) = (-a)/(b)` ...[∵ Reciprocal of –1 = –1]
(iv) Given, `a/b ÷ (-a)/b = a/b xx ((-b)/a) = -1` ...`[∵ "Reciprocal of" (-a)/b = (-b)/a]`
(v) Given, `b/a ÷ (d/c) = b/a xx c/d = (bc)/(ad)` ...`[∵ "Reciprocal of " d/c = c/d]`
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