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Ln a cuboid, the sum of the squares of its three dimensions is equal to half of its total surface area. If the volume of the cuboid is 729 cm3, then find its lateral surface area (in cm2).

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Question

ln a cuboid, the sum of the squares of its three dimensions is equal to half of its total surface area. If the volume of the cuboid is 729 cm3, then find its lateral surface area (in cm2).

Options

  • 648

  • 576

  • 900

  • 324

MCQ
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Solution

324

Explanation:

Let, dimensions of cuboid are `l`, b and h.

A.T.Q,

`l^2 + b^2 + h^2 = 1/2 xx 2(lb + bh + hl)`

⇒ `l^2 + b^2 + h^2 = lb + bh + hl`

⇒ `l^2 + b^2 + h^2 - lb - bh - hl` = 0

⇒ `1/2 (2l^2 + 2b^2 + 2h^2 - 2lb - 2bh - 2hl)` = 0

⇒ `(1 - b)^2 + (b - h)^2 + (h - l)^2` = 0

Therefore, `l = b = h`

Given, Volume of cuboid = 729 cm3

`l xx b xx h` = 729 cm3, `l^3` = 729 cm3

∴ `l` = 9 cm

Lateral surface area = `2(l + b) xx h`

= `2(l + l) xx l`

= 2(9 + 9) × 9

= 324

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Data Interpretation (Entrance Exam)
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